3x^2-400x+10000=0

Solution for 3x^2-400x+10000=0 equation:

3x^2-400x+10000=0

a = 3; b = -400; c = +10000;
Δ = b2-4ac
Δ = -4002-4·3·10000
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-400)-200}{2*3}=\frac{200}{6}
=33+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-400)+200}{2*3}=\frac{600}{6}
=100
$